-y-28+y^2=2y+2y^2

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Solution for -y-28+y^2=2y+2y^2 equation: 



-y-28+y^2=2y+2y^2

We move all terms to the left:

-y-28+y^2-(2y+2y^2)=0

We add all the numbers together, and all the variables

y^2-(2y+2y^2)-1y-28=0

We get rid of parentheses

y^2-2y^2-2y-1y-28=0

We add all the numbers together, and all the variables

-1y^2-3y-28=0

a = -1; b = -3; c = -28;
Δ = b2-4ac
Δ = -32-4·(-1)·(-28)
Δ = -103
Delta is less than zero, so there is no solution for the equation

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